Right shifts the bits of an expression, maintaining sign.

expression1 |

# Arguments

*expression1*-
Any numeric expression.

*expression2*-
Any numeric expression.

# Remarks

The **>>** operator shifts the bits of *expression1* right by the number of bits specified in *expression2*. The sign bit of *expression1* is used to fill the digits from the left. Digits shifted off to the right are discarded. The data type of *expression1* determines the data type returned by this operator.

The **>>** operator masks *expression2* to avoid shifting *expression1* by too much. Otherwise, if the shift amount exceeded the number of bits in the data type of *expression1*, all the original bits would be shifted away to give a trivial result. To ensure that each shift leaves at least one of the original bits, the shift operators use the following formula to calculate the actual shift amount: mask *expression2* (using the bitwise AND operator) with one less than the number of bits in *expression1*.

# Example

For example, after the following code is evaluated, *temp* has a value of -4: -14 (11110010 in binary) shifted right two bits equals -4 (11111100 in binary).

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var temp temp = -14 |

To illustrate how the masking works, consider the following example.

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var x : byte = 15; // A byte stores 8 bits. // The bits stored in x are 00001111 var y : byte = x |