Javascript debugger
Website design
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This will return the contents of the output buffer or FALSE, if output
buffering isn't active.
<?php
ob_start();
echo "Hello ";
$out1 = ob_get_contents();
echo "World";
$out2 = ob_get_contents();
ob_end_clean();
var_dump($out1, $out2);
?>The above example will output:
string(6) "Hello "
string(11) "Hello World"
| ob_start() |
| ob_get_length() |